java - infinite loop while accessing resource folder -


in spring project have written filter handle requests.it works fine, while accessing resource infinite loop happening.

i defined resource folder under class extends webmvcconfigureradapter code used define resource folder:-

this request url:

@override public void addresourcehandlers(resourcehandlerregistry registry) {     registry.addresourcehandler("/resources/**").addresourcelocations("/resources/"); } http://localhost:8080/abc/resources/images/chart/receivableaccounts.png

while accessing url through browser request proceesing number of times in console(eclipse).

i can't identify what's real problem is.

here requestfilter:

package org.abc.app.config;  import java.io.ioexception;  import javax.servlet.filter; import javax.servlet.filterchain; import javax.servlet.filterconfig; import javax.servlet.servletexception; import javax.servlet.servletrequest; import javax.servlet.servletresponse; import javax.servlet.http.httpservletrequest; import javax.servlet.http.httpservletresponse;  import org.apache.log4j.logmanager; import org.apache.log4j.logger; import org.businesscognizance.app.util.session;  /** * <b>custom filter created handling incoming,outgoing  requests</b> *  * @author jishnu *  */  public class requestfilter implements filter {  private static logger logger =  logmanager.getlogger(requestfilter.class);  @override public void init(filterconfig filterconfig) throws servletexception {  }  @override public void dofilter(servletrequest request, servletresponse response,  filterchain chain)         throws ioexception, servletexception {     httpservletresponse httpservletresponse = (httpservletresponse) response;     httpservletrequest httpservletrequest = (httpservletrequest) request;     string context = httpservletrequest.getcontextpath();     string requesturi = httpservletrequest.getrequesturi();     int status = httpservletresponse.getstatus();     system.out.println("hey there>>>>" + requesturi + "check this" + context + "/resources");     if (isauthenticated(httpservletrequest) || requesturi.equals(context + "/login")             || requesturi.startswith(context + "/resources")) {          logger.info("access granted device ip address" + " '" + httpservletrequest.getremoteaddr() + "' "                 + "for requested url" + " '" + httpservletrequest.getrequesturl() + "'");          if (isauthorized()) {          } else {             httpservletresponse.reset();             httpservletresponse.setstatus(httpservletresponse.sc_forbidden);             return;          }         chain.dofilter(request, response);      }      else {         httpservletresponse.reset();         if (status == httpservletresponse.sc_accepted || status == httpservletresponse.sc_ok) {             httpservletresponse.setstatus(httpservletresponse.sc_bad_request);         } else {             httpservletresponse.setstatus(status);         }         httpservletresponse.getwriter().println("server rejected request");          return;      }  }  @override public void destroy() {  }  public boolean isauthorized() {     return true; }  public boolean isauthenticated(httpservletrequest request) {     string accesstoken = request.getheader("access_token");     boolean result = false;     if (accesstoken != null) {         if (session.iftokenexists(accesstoken)) {             result = true;         }      }      return result; }

}

if need further please let me know.

any suggestion useful.

thank you

it seems hokey implementation of:

  1. a pre-authenticated request.
  2. request static resources.

this looks straight outta 2003 codebase; suggest start extending onceperrequestfilter , make filter @component. since isauthorized method nothing, can straightaway bypass filter urls overriding shouldnotfilter method. , have read javadoc httpservletresponse? calling reset resets status code, kinda code useless status == httpservletresponse.sc_accepted || status == httpservletresponse.sc_ok.

i know doesn't address so-called infinite loop problem, once clean up, may not have such issue. last not least, debugger; you've code, don't.


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