sql - PHP json_encode returns false -
i trying these data db , stuck @ case in query.
i trying so:
(case when e.email = null c.user end) email
basically want in case e.email turns null, want c.user e-mail. not working , new "advanced sql".
you want coalesce
, return first non-null argument:
coalesce(e.email, c.user) email
by way, in sql null = null
returns null
. have use is
comparison operator when checking if value null i.e. e.email null
opposed e.email = null
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