python - Populating Array with an indexed array -


i have numpy array called "precip" shape (2,3,3) corresponds (time, lat, lon)

array([[[ 0.05368402,  0.43843025,  0.09521903],         [ 0.22627141,  0.12920409,  0.17039465],         [ 0.48148674,  0.59170703,  0.41321763]],          [[ 0.63621704,  0.11119242,  0.25992372],         [ 0.67846732,  0.3710733 ,  0.25641174],         [ 0.1992151 ,  0.86837441,  0.80136514]]])

i have numpy array called "idx" list of indices, shape (3, 4):

array([[0,0,1,1], # time        [0,2,0,2],  # x coordinate        [0,2,0,2]]) # y coordinate

so far have been able index "precip" variable "idx" variable array shape (4,), ie.

>>>accum = precip[idx[0,:],idx[1,:],idx[2,:]] array([ 0.05368402,  0.41321763,  0.63621704,  0.80136514])

but, need array of zeros "accum" shape (3,3), populated sum of "precip" each pair of coordinates in "idx". other gridpoints not listed in "idx" 0.

basically want array "accum" looks this

>>>accum     array([[[ 0.68990106, 0. , 0.        ], # 0.68990106 = 0.05368402 + 0.63621704         [ 0.        , 0. , 0.        ],          [ 0.        , 0. , 1.21458277], # 1.21458277 =  0.41321763 + 0.80136514

i'd appreciate help! :)

if understand correctly need is:

array = [0.5] * 249

it return array of length 249 populated 0.5 in each index. after can slice if necesary retrieve amount of elements like.

if not want, can use dictionaries , add key tuple want way.

dict = {(40, 249): array}

i hope helps.


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