Django url from a huge list of words from a file -


i have file 60,000 words, need url valid when contains of words in file 

url(r'^site/keyword/$', 'mysite.views.home')

so need keyword 1 of words present in file.

i know can use pipe multiple words list large that

don't in url; in view.

def my_view(request, word):     if word not in words:         raise http404()

for best performance, words should set defined @ module level.


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