python - How to pass an instance method, that uses instance variables, as argument to another function? -

i want pass method foo of instance of class a function run_function. method foo use instance variables of class a.

here minimal example, in instance variable of a self.a_var, , foo prints variable.

class a:     def __init__(self,a_var):         self.a_var=a_var     def foo(self):         print(self.a_var)   class b:     def __init__(self, a):         self.a=a          # edit (comment compile)         self.a.do_something()      def run_function(self):         self.a.foo()     def run_function_2(self, bar):         bar()    mya = a(42) mya.foo()  # current implementation myb=b(mya) myb.run_function()  # better(?) implementation myb.run_function_2(mya.foo) 

at moment pass instance mya of class a instance of b , explicitly call self.a.foo(). forces name of function of ato foo. stupid.

the better (?) implementation passes function of instance run_function2. works, not sure if "safe".

question:

are there loopholes don't see @ moment?

the important part is, method foo, passed, needs access instance variables of (its) class instance. so, foo called inside run_function_2 have access instance variables of mya?

is there better way implement this?

edit: forgot add, class b have instance of a, since has do_something instance. maybe change something(?). sorry!

for second implementation, have considered following:

>>> myaa = a(42) >>> myab = a(43) >>> myb = b(myab) >>> myb.run_function_2(myaa.foo) 42 

this might not want. how using getattr() , passing in desired method name:

>>> class c: ...     def __init__(self, a): ...             self.a = ...     def run_fct(self, bar): ...             fct = getattr(self.a, bar) ...             fct() ...  >>> myc = c(myaa) >>> myc.run_fct('foo') 42