dataframe - R: Using which() with output of quantile()? -


i'm new r, sorry if weird question.

so, i'm trying value in column data frame df, 90th percentile of column b. used following code value @ quantile:

p = quantile(df$b, c(0.9))

after this, wanted use row number of value, use corresponding value in column a:

which(df$b == p)

but reason gives output of

integer(0)

i substituted variable, p, actual value, 1.68, , worked, , creating variable 1.68 works too, using result of quantile never gives right value.

i've tried using as.numeric, using p[[1]] , as.double. no change result whatsoever. appreciated in understanding why happens , if there's way go this.

edit: clarify, there entries @ 90th percentile, , using hard coded value returned quantile function return these. problem occurs in function when use output of quantile.

'quantile' give the 90% percentile of data may or may not value in data therefore if want value closest 90% percentile need match little differently:

your data:

df <- data.frame(b = runif(50))

the 90th percentile

p = quantile(df$b, c(0.9))

the index closest 90th percentile:

index <- which(abs(df$b - p) == (min(abs(df$b - p), na.rm = true))) index

get value(s) dataframe using index:

df$b[index]

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