mysql - Sub-Select required in Sequelize include -


i have ignore rows fetched include in sequelize query. friend showed me how work in sql have no idea how map sequelize.

i tried things group , distinct, don't work required.

this sequelize query:

surveysuggestdate.findall({     where: {         surveysforeignkey: survey.surveysid     },     include: [         { model: surveytime },         { model: surveyanswer }     ],     order: [         [ 'date', 'asc' ]     ] }).then((datetimeanswers) => {     resolve(datetimeanswers); }).catch((error) => {     reject(error); });

the model surveytime has column "time" appears @ least twice in database. have ignore these records , use latest one.

this sql code generated sequelize code above:

select `surveysuggestdate`.`suggestdate_id`     `suggestdateid`,         `surveysuggestdate`.`date`               `date`,         `surveysuggestdate`.`datestring`         `datestring`,         `surveysuggestdate`.`fieldcnt`           `fieldcount`,         `surveysuggestdate`.`surveys_id_fk`      `surveysforeignkey`,         `surveysuggestdate`.`disabled`           `disabled`,         `surveysuggestdate`.`surveys_id_fk`,         `surveytimes`.`times_id`                 `surveytimes.timeid`,         `surveytimes`.`time`                     `surveytimes.time`,         `surveytimes`.`position`                 `surveytimes.position`,         `surveytimes`.`fieldcnt`                 `surveytimes.fieldcount`,         `surveytimes`.`suggestdate_id_fk`                `surveytimes.suggestdateforeignkey`,         `surveytimes`.`disabled`                 `surveytimes.disabled`,         `surveytimes`.`suggestdate_id_fk`                `surveytimes.suggestdate_id_fk`,         `surveyanswer`.`answers_id`              `surveyanswer.answerid`,         `surveyanswer`.`answer_suggest_id`               `surveyanswer.answersuggestid`,         `surveyanswer`.`answer_suggestdate_id`           `surveyanswer.answersuggestdateid`,         `surveyanswer`.`answer_time_id`          `surveyanswer.answertimeid`,         `surveyanswer`.`answer`                  `surveyanswer.answer`,         `surveyanswer`.`surveys_id_fk`                   `surveyanswer.surveysforeignkey`,         `surveyanswer`.`answers_usernames_id_fk`         `surveyanswer.answerusernameforeignkey`,         `surveyanswer`.`disabled`                `surveyanswer.disabled`,         `surveyanswer`.`created`                 `surveyanswer.created`,         `surveyanswer`.`surveys_id_fk`           `surveyanswer.surveys_id_fk`,         `surveyanswer`.`answer_suggest_id`               `surveyanswer.answer_suggest_id`,         `surveyanswer`.`answer_suggestdate_id`           `surveyanswer.answer_suggestdate_id`,         `surveyanswer`.`answer_time_id`          `surveyanswer.answer_time_id`         ,         `surveyanswer`.`answers_usernames_id_fk`         `surveyanswer.answers_usernames_id_fk`    `surveys_suggestdate` `surveysuggestdate`         left outer join `surveys_times` `surveytimes`                      on `surveysuggestdate`.`suggestdate_id` =                         `surveytimes`.`suggestdate_id_fk`         left outer join `surveys_answers` `surveyanswer`                      on `surveysuggestdate`.`suggestdate_id` =                         `surveyanswer`.`answer_suggestdate_id`   `surveysuggestdate`.`surveys_id_fk` = 2025  order  `surveysuggestdate`.`date` asc;

to achive goal mentioned friend told me replace first left outer join sub select. one:

left outer join  (           select   max(`times_id`) `times_id`,                    `time`,                    `position`,                    `fieldcnt`,                    `suggestdate_id_fk`,                    `disabled`               `surveys_times`           group `time`,                    `position`,                    `fieldcnt`,                    `suggestdate_id_fk`,                    `disabled`)     `surveytimes`

any idea how in sequelize? or in general: how skip duplicate values of specific column inside of included model , take 1 highest id?

thank in advance!


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