php - Jquery not getting dynamic dropdown value -


in code when selecting 1st dropdown getting value in next not getting value jquery ..

<?php $con=mysql_connect('localhost','root','root'); mysql_select_db('alok',$con); ?> <!doctype html> <html> <head>     <title></title>     <script type="text/javascript" src="jquery.min.js"></script> </head> <body> <form method="post"> <table width="100%">     <tr>         <td>id</td>         <td>item</td>         <td>status</td>         <td>dropdown</td>     </tr>     <?php      $query="select * jain";     $result=mysql_query($query);     while($row=mysql_fetch_array($result)){       ?>     <tr>         <td><?php echo $row['id']; ?></td>         <td><?php echo $row['gift']; ?>         </td>         <td><?php if($row['status']==='0'){echo 'pending';}elseif($row['status']==='1'){echo 'recieved';}else{             echo 'rejected';} ?></td>          <td>              <select name="status" id="status">                 <option value="0">pending</option>                 <option value="1">recieved</option>                 <option value="2">rejected</option>             </select>         </td>      </tr>     <?php } ?> </table> </form> </body> </html> <script type="text/javascript">     $(document).ready(function(){     $('#status').change(function(){         var status=$('#status option:selected').val();         alert(status);     })     })  </script>

when selecting first dropdown: enter image description here

when selecting second dropdown not getting alert: enter image description here

what doing wrong here please let me know newbie here

use different id select. other selected value.

<select name="status" id="status1">     <option value="0">pending</option>     <option value="1">recieved</option>     <option value="2">rejected</option> </select> <select name="status" id="status2">     <option value="0">pending</option>     <option value="1">recieved</option>     <option value="2">rejected</option> </select>

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