sql - Aging - Calendar and Business Days Different Records of Data -


i using sql server 2012 , have aging question. tried include sample data below 4 records.

filenumber    filetype     completeddate  90440        internal      8/11/2017  90440        strategy       null  90441        internal      8/10/2017  90441        strategy       null

a strategies' aging calculated internal filetype's completed date way strategy filetype's completed date. every filenumber can have multiple filetypes associated it. if strategy's completed date null, internal filetype's completed date way today's date or getdate().

so i'm trying show count of pending strategies , current aging in business , calendar days...so want data return this. 

file number    filetype    agebusiness  agecalendar  90440          strategy     2            4  90441          strategy     3            5

any clue on how go this? appreciated.

something may work i'm not 100% sure since depends on sort of filetypes in table, whether accounting holidays, happens when strategy (or whatever latest file type) has value completed date.

;with internal (     select  filenumber, filetype,             datediff(day,completeddate,getdate())- (datediff(wk, completeddate, getdate()) * 2) -                 case when datepart(dw, completeddate) = 1 1 else 0 end +                 case when datepart(dw, getdate()) = 1 1 else 0 end agebusiness,             datediff(day,completeddate,getdate()) agecalendar     @test     filetype = 'internal' ) select t.filenumber, t.filetype, i.agebusiness, i.agecalendar @test t inner join internal on     (t.filenumber = i.filenumber) completeddate null

the problem above wouldn't show row if strategy (or whatever latest file type) has completed date. therefore may want like

;with internal (     select  filenumber, filetype,             datediff(day,completeddate,getdate())- (datediff(wk, completeddate, getdate()) * 2) -                 case when datepart(dw, completeddate) = 1 1 else 0 end +                 case when datepart(dw, getdate()) = 1 1 else 0 end agebusiness,             datediff(day,completeddate,getdate()) agecalendar     @test     filetype = 'internal' ), latest (     select filenumber, filetype, rank() on            (partition filenumber order coalesce(completeddate,getdate()) desc) rnk     @test ) select l.filenumber, l.filetype, i.agebusiness, i.agecalendar latest l inner join internal on     (l.filenumber = i.filenumber) rnk = 1

where show row regardless of if it's null or not, @ expense of adding rank() more intensive.


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