Parse error: syntax error, unexpected '$data' (T_VARIABLE) in C:\wamp64\www\web\test.php on line 27 -


this question has answer here:

so error , can't understand why. in opinion syntax correct, still doesn't work way want. maybe don't understand mysql syntax in php

<?php include 'db.php';  $data = array( 0 => array( 'comment_author_name' => 'jurgis', 'comment_author_rank' => 'pro', 'comment_date' => '2017-08-13 23:45:23', 'comment_message' => 'lorem ipsum (trump. lipsum) yra tekstas naudojamas  spaudos ir grafinio dizaino industrijoje jau nuo xvi amžiaus pradžios.' ), 1 => array( 'comment_author_name' => 'martynas', 'comment_author_rank' => 'newbie', 'comment_date' => '2017-08-14 13:32:15', 'comment_message' => 'jis naudojamas parodyti grafinio pristatymo elementus,  tokius kaip tipografija, dizainas ar šriftas.' ), 2 => array( 'comment_author_name' => 'tomas', 'comment_author_rank' => 'master', 'comment_date' => '2017-08-14 13:42:20', 'comment_message' => 'jis taip pat kūrimo stadijoje naudojamas kaip kai  kurių produktų aprašymų tekstas, prieš tai kai įrašomas tikrasis tekstas.'   ) );    for($i=0; $i<count($data); $i++){     $query = "insert discussion_info      (comment_author_name,comment_author_rank,comment_date,comment_message)            values ('"$data[$i]['comment_author_name']"',                   '"$data[$i]['comment_author_rank']"',                   '"$data[$i]['comment_date']"',                   '"$data[$i]['comment_message']"')";      $mysqli_query($connection, $sql);    } ?>

you need concat string var data. this: 

 values ('" . $data[$i]['comment_author_name'] . "',

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