vba - Function uses intellisense to accept multiple Enums -


i have enum declared in vba

enum myenum     vala = 3     valb = 17     valc = 20 end enum

i function accepts combination of values specified enum, , employs intellisense when enter them. i.e., prompts me possible values can input.

now if choose values in enum powers of two, chip pearson suggests in his section on composite values, namely

function myfunction(val myenum)     '... end function

usage

debug.print myfunction(vala + valb) 'with intellisense

however enums not follow pattern, there's no way can think of discern whether vala + valb input, or valc example. therefore i'm wondering:

is there way pass array/undetermined number of variables function, whilst still using intellisense suggest possible values?

no, there isn't. flag enums use powers of 2 that.

public enum foo     v1 = 2 ^ 0     v2 = 2 ^ 1     v3 = 2 ^ 2     v4 = 2 ^ 3     v5 = 2 ^ 4     '... end enum

the reason allow use bitwise logic determine bits "on", given composite value, example 5 can 4 + 1:

power    2^5  2^4 2^3  2^2  2^1  2^0  value     32   16   8    4    2    1 bit        0    0   0    1    0    1

as already mentioned, way use paramarray parameter, can ever variant, , can ever passed byref, not means lose intellisense, lose semantic safety of passing parameter values byval (well, code implicitly passes byref anyway).

so either come way "map" individual "magic underlying values" enum members flag enum members (with powers of 2), or forfeit intellisense.

private function getflag(byval value myenum) myflagenum     static converter scripting.dictionary     if converter nothing         set converter = new scripting.dictionary         converter             .add myenum.vala, myflagenum.valuea             .add myenum.valb, myflagenum.valueb             .add myenum.valc, myflagenum.valuec             .add myenum.vald, myflagenum.valued             .add myenum.vale, myflagenum.valuee         end     end if     getflag = converter(value) end function

and can combine them after pulling mapped value:

debug.print myfunction(getflag(vala) + getflag(valb)) ' intellisense everywhere!

where myfunction takes myflagenum value.

if underlying values have specific meaning , they're carved in stone , myfunction needs use them, need function "unwrap" individual flagenum values individual "myenum" values:

private function getfromflag(byval value myflagenum) myenum     static converter scripting.dictionary     if converter nothing         set converter = new scripting.dictionary         converter             .add myflagenum.valuea, myflagenum.vala             .add myflagenum.valueb, myflagenum.valb             .add myflagenum.valuec, myflagenum.valc             .add myflagenum.valued, myflagenum.vald             .add myflagenum.valuee, myflagenum.vale         end     end if     getfromflag = converter(value) end function

and again, use function with individual not combined values. first thing myfunction needs determine individual flags "on", , getfromflag each 1 of them individual non-flag enum values.

this should useful:

private function hasflag(byval composite long, byval flag long) boolean     hasflag = (composite , flag) = flag end function

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