nested if else syntax error php -


this question has answer here:

   says syntax error t_else, problem?

it making me crazy finding did wrong in code myy mistake here?

<?php include("../mysql_connect.php"); if (isset($_post['search_form'])) {     $page1 = $_get['page'];     if ($page1 == "" || $page1 == 1) {         $page1 = 0;     }     else {         $page1 = ($page1 * 5) - 5;     }     $query = "select * tbl_news news_title '$_post[search]' || news_author '$_post[search]' ";     $result = mysql_query($query);     while ($row = mysql_fetch_array($result)) {         ?>         <table class="table table-hover" border="2">             <col width="50%"></col>             <col width="40%"></col>             <col width="20%"></col>             <tr>                 <td rowspan="3">                     href="news_view.php?id=<?php echo $row['news_id']; ?>">                     <img src="<?php echo $row['news_image_location'] . $row['news_image']; ?>" height="300" width="500">                     </a>                 </td>                 <td>title: <?php echo $row['news_title']; ?></td>              </tr>             <tr>                 <td>author: <?php echo $row['news_author']; ?></td>             </tr>              <tr>                 <td>date: <?php echo $row['news_date_filed']; ?></td>             </tr>             </thead>         </table>         <?php     }     $query1 = "select * tbl_news news_title '$_post[search]' || news_author '$_post[search]'";     $result1 = mysql_query($query1);     $row1 = mysql_num_rows($result1);     $pagecount = $row1 / 5;     $pagecount = ceil($pagecount);      ($count = 1; $count <= $pagecount; $count++) {         ?>          <a href="news.php?page=<?php echo $count; ?>"><?php echo $count ?></a>          <?php     } } else{     $page1 = $_get['page'];     if ($page1 == "" || $page1 == 1) {         $page1 = 0;     }     else {         $page1 = ($page1 * 5) - 5;     }     $query = "select * tbl_news news_status='active' limit $page1,5";     $result = mysql_query($query);     while ($row = mysql_fetch_array($result)) {         ?>         <table class="table table-hover" border="2">             <col width="50%"></col>             <col width="40%"></col>             <col width="20%"></col>             <tr>                 <td rowspan="3">                     <a href="news_view.php?id=<?php echo $row['news_id']; ?>">                         <img src="<?php echo $row['news_image_location'] . $row['news_image']; ?>" height="300"                              width="500">                     </a>                 </td>                 <td>title: <?php echo $row['news_title']; ?></td>              </tr>             <tr>                 <td>author: <?php echo $row['news_author']; ?></td>             </tr>              <tr>                 <td>date: <?php echo $row['news_date_filed']; ?></td>             </tr>             </thead>         </table>         <?php     }     ?>     <?php     $query1 = "select * tbl_news news_status='active'";     $result1 = mysql_query($query1);     $row1 = mysql_num_rows($result1);     $pagecount = $row1 / 5;     $pagecount = ceil($pagecount);      ($count = 1; $count <= $pagecount; $count++) {         ?>          <a href="news.php?page=<?php echo $count; ?>"><?php echo $count ?></a>          <?php # code...     } } ?>

here full code, of errror gives me, please me guys takes me a lot of time having kind of problem tried maybe guys me solve problem hahahaha drained mind here , im mindblown on facing problem

you missing < @ tag inside first while loop (exactly on line 21 when copy/paste code). might reason doesn't recognize else statement, because can't properly.


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