python - Web Scraping - blank return -


could please explain me why blank return when running code? trying print contents of html tag using beautiful soup. code below.

thanks

import urllib3 urllib3.disable_warnings(urllib3.exceptions.insecurerequestwarning)  bs4 import beautifulsoup http = urllib3.poolmanager()  def stats():  url = 'https://www.flashscore.com.au/football/usa/mls/results/'   response = http.request('get', url)  soup = beautifulsoup(response.data,'lxml')  right_table=soup.find('div',{'class':'fs-table tournament-page'})  print(right_table.text)  stats()

you can fetch , process multiple urls using pyqt5 ask in comment this:

from pyqt5.qtgui import * pyqt5.qtcore import * pyqt5.qtwebkit import * pyqt5.qtwebkitwidgets import qwebpage pyqt5.qtwidgets import qapplication import bs4 bs import sys   class render(qwebpage):     def __init__(self):         super(render, self).__init__()         self.mainframe().loadfinished.connect(self.handleloadfinished)      def start(self, urls):         self._urls = iter(urls)         self.fetchnext()      def fetchnext(self):         try:             url = next(self._urls)         except stopiteration:             return false         else:             self.mainframe().load(qurl(url))         return true      def processcurrentpage(self):         print (self.mainframe().url().tostring())         result = self.mainframe().tohtml()         soup = bs.beautifulsoup(result, 'lxml')         right_table = soup.find('div', {'class': 'fs-table tournament-page'})         print(right_table.text)      def handleloadfinished(self):         self.processcurrentpage()         if not self.fetchnext():             app.quit()   if __name__ == '__main__':     urls = ["https://www.flashscore.com.au/football/usa/mls/results/", "https://www.flashscore.com.au/football/usa/mls/fixtures/"]     app = qapplication(sys.argv)     renderer = render()     renderer.start(urls)     sys.exit(app.exec_())

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