Comparison, exclusion, and popping elements from a list (Python) -

i want compare number (dist) against each element of sorted list (my list).

if number smaller first element in mylist, have proceed , find right place dist, eliminate first element in mylist , shift list.

my main problem tha case when dist smaller 1st elemnt in mylist. index out of range ...

dist = 10 mylist = [40, 30, 20, 15] # sorted list  j in range(0, len(mylist)):     if mylist[j] < dist &  dist> mylist[j+1]:         print (mylist[j], '<' ,dist, '>', mylist[j+1])         #drop 40         #shift list becomes: [30,20, 15,10] 

iiuc, want insert dist @ right position , knock off first element. fine, have few issues. major 1 being condition, , i'm not talking &. you'll want make sure dist greater current, lesser next. this:

if mylist[j] < dist < mylist[j+1]: 

you'll have run till 1 lesser len(mylist) avoid index out of bounds.

another trick can use for...else work corner case dist not inserted anywhere else.

in short, try this:

for j in range(len(mylist) - 1):     if mylist[j] < dist < mylist[j + 1]:          mylist.insert(j, dist)          mylist = mylist[1:]          break else:     mylist.append(dist)     mylist = mylist[1:] 

alternatively, can run 1 len(mylist), , compare check mylist[j - 1] < dist < mylist[j].