javascript - Need a more efficient way to clear unresourceful setInterval() id's -

i in situation had create clear array of setinterval() methods:

let intervals = []  for(let i=0; i<10; i++){   intervals.push( setinterval( function(){}, 1000 ) ) }  for(let i=0; i<10; i++){   clearinterval( intervals[i] ) } 

but whatever reason didn't work. came across this:

for (let i=1; i<9999; i++){   window.clearinterval(i) } 

which worked perfectly, why should have use performance threatening hack clear bunch of intervals? noticed when logging interval id's this:

function makeintervals(){    let intervals = []    for(let i=0; i<10; i++){     intervals.push( setinterval( function(){}, 1000 ) )   }    console.log( 'interval id\'s: ' + intervals )    for(let i=0; i<10; i++){     clearinterval( intervals[i] )   }  }  makeintervals() // interval id's: 5,6,7,8,9,10,11,12,13,14 makeintervals() // interval id's: 15,16,17,18,19,20,21,22,23,24 makeintervals() // interval id's: 25,26,27,28,29,30,31,32,33,34 

you can see though old intervals cleared, new interval id's still being incremented , assigned each new setinterval().

is there reason creating new, incremented interval id's though previous id's cleared?

why not throw old id's pool instead of looping 9999+ times, have loop 10 times?

need more efficient way clear unresourceful setinterval() id's !

cheers.

edit: reason being such stickler because i'm using recursive function create new setinterval()'s , clear old ones. sooner or later 9999+ loops of clearinterval() wouldn't enough.

i think getting confused in thinking clearintervals(interval[i]) removing element i intervals array, not doing. once clear interval, there no reason store reference it, should remove array using array.splice:

for (let = 0; < 10; i++){     clearinterval(intervals[i]);     intervals.splice(i, 1); // remove element array } 

now, when call function again, previous elements no longer exist in array start on @ 0.

also, instead of assuming array length 10, if want loop entire array should use array.length:

for (let = 0; < intervals.length; i++){     clearinterval(intervals[i]);     intervals.splice(i, 1); }